By simply extending the principle presented in the Meno dialog
It is possible to do this fairly easily, by simply extending the principle presented in the Meno dialog, and applying it to all right triangles. In this case one would mirror the triangles into rectangles, and put four of them together, as in the Meno dialog. One would thereby simply stretch the squares of the Meno dialog, into rectangles. Would this be enough to prove the point?
Pythagoras proposed that the area of Csquare is equal in size to the areas of Asquare and Bsquare added together. Can we prove this to be so in this extended case?
Certainly we can. We can proof this the same way as before.
