We can do this by counting triangles
We can do this by counting triangles. The Csquare is again made up of 4 triangles, plus the big red area in the middle. I propose that we now create a construct that is twice as large in area as Csquare, and proof to ourselves that we can place two Asquares, and two Bsquares into it. If we can do this, we have delivered proof of the Pythagorean theorem for all cases.
The proof lies in that we can prove that Csquare covers precisely half of the area that we can place two Asquares, and two Bsquares into.
